Question

2. Consider a gas container with a movable piston. The container is separated from a water bath by a diathermal wall. Note, the water bath is separated from the external surroundings by an adiabatic wall. Assume that the interior of the gas container is your thermodynamics system and the water bath has a temperature, Tbath. Assume as well that the volume of the water bath is relatively large to that of the system a. What is the temperature of the gas container if the volume of the container remains constant? Justify your answer. b. What happens to the temperature of the system and the water bath after compression of the gas from an initial volume to a final volume? Again, assume a very large water bath. Justify your answer

Answer 1

A Diathermal wall is transparent to heat transfer between system and surroundings.

Assumptions:
(i)Water bath is separated from external surroundings with an adiabatic wall i.e No Heat Transfer between water bath and external surroundings
(ii)Volume of water bath very large as compared to that of container.

(a) Consider fig. a below, system is at temperature T₁ and Volume V₁. As we can see that the container is separated by a diathermal wall from the water bath hence the system will be in thermal equilibrium with the water bath i.e T₁ =T_bath

, , , , , , , , , , water bath it bath) f

(b) Consider fig. b below, after compression from volume V₁ to V₂, there will be rise in temperature of the system from T₁ to T₂. Temperatures T₂ > T_bath. As volume of the water bath is much higher as compared to that of container there would not be any significant rise in temperature of water bath.

water bathi

Please rate!!

Thank you!!

, , , , , , , , , , water bath it bath) f

water bathi

, , , , , , , , , , water bath it bath) f

We were unable to transcribe this image