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3. 15 points KatzPSE1 29.P.060 My Notes Ask Your Teacher The figure below shows a simple RC circuit with a 1.50-uF capacitor,

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Answer #1

A)

Charge, Q = Qo (1 - e^-t/RC)

Q = 1.5 x 9 (1 - e^-(6.5/(3.2 x 1.5)) = 10.01 uC

B)

Current, I = (V/R) e^-t/RC

I = (9/3.2 x 10^6) e^-(6.5/3.2 x 1.5) = 0.73 uA

C)

dE/dt = Q/C x I = (10.01/1.5) x 0.73 = 4.87 uW

D)

Power, P = VI = 9 x 0.73 = 6.57 uW

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