A certain drawbridge can be modeled as a uniform 1.60×104 N bar, 12.0 m long, pivoted about its lower end. When this bridge is raised to an angle of 60.0 ∘ above the horizontal, the cable holding it suddenly breaks, allowing the bridge to fall. At the instant after the cable breaks,
a. At the instant after the cable breaks what is the torque on this bridge about the pivot?
b. At the instant after the cable breaks at what rate is its angular momentum changing?
a) Torque = m*g*(L/2)*sin(90 - 60)
= 1.60*10^4*(12/2)*sin(30)
= 48000 N.m
b) rate of change of angular momentum = T
= 48000 kg.m^2/s^2 (or) N.m
A certain drawbridge can be modeled as a uniform 1.60×104 N bar, 12.0 m long, pivoted...
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