PLEASE SHOW WORKHomework Answers
HoSoln is positive. So, heat wil be released by water
heat absorbed = mol*HoSoln
= 0.15 mol * 17.2 KJ/mol
= 2.58 KJ
= 2580 J
This heat will decrease temperature of water
Since density of water is 1 g/mL and volume is 150 mL:
mass of water = 150 g
specific heat capacity of water, C = 4.184 J/g.oC
use:
Q = m*C*(Tf - Ti)
2580 J = 150 g * 4.184 J/g.oC*(25-Tf) oC
(25-Tf) = 4 oC
Tf = 21 oC
Answer: B
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PLEASE SHOW WORK
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