A person walks 20.0° north of east for 3.06 km. How far would she have to...
A person walks 20.0° north of east for 3.06 km. How far would she have to walk due north and due east to arrive at the same location?
| ____ km (due north) |
| ____ km (due east) |
Homework Answers
sin (20) = O/H
O = sin (20) * 3.06
O = 1.04658 km north
cos (20) = A/H
A= cos(20) * 3.06
A = 2.8754 km east
total = 3.922 km
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