1.
Barbara travels 20 km east, 40 km north, then 50km west. She returned to the starting point along a straight line. Then it must be the displacement between the two points.the net displacement between 20 km east and 50 km west is 30 km west.
The distance she must walk S = (302 + 402 )1/2 = 50 km
2. tan θ = 30/40 ; θ = tan-1 (30/40) = 36.80
the last leg of Barbara’s travel makes an angle of 36.80 East of South
Barbara travels 20 km East, then 40 km North, then 50 km West. She then walks...
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