Question

A rotator spinning with constant w has friction along the bottom of the tube only (usmg). The side of the tube does not have friction. A small mass m is at rest inside the tube at r = ro. Find the following in variable form). A Determine the maximum value for (w) where the mass overcomes static friction. B. Assume the mass starts to move at this maximum w a constant). If the mass moves against the kinetic friction (Hkmg). Solve the location based differential equation that represents V ). C. Develop the time based solution for r(e). Where =wt. TETTE

Answer 1

Uw Mawa 7711TYTTITI mg FBD of small mass y 7 N omrwa re here Nang AX for maxim value of w f = f (static friction) fe= M img] { Fu = 0 = f = mew2; rinko. Имя = m, ma Tuomax = Me & Answers

By W = Mg & f = fx = 14 mg. : Etu-ma here. » mwez-Ming = ma; düzro 1C => 1 Ms IdaM ; V- velocity of small mass at time to Answer. cy from egno Vente enda 2-M18 qvodu bika) - Hughes e = CD) 43) - Mug (10-to) vs M22 (1-46) - 2+3 (1:0) am - M428 (-thre) - 2468(8-8) tro 110 Answer