Here gas expand isobarically(constant pressure process).
Since pressure for this process is a constant, force exerted by the system is constant .
Therefore work done of the system is giv by W = -PΔV
volume changes from 2.45 L to 6.82 L thus, volume change , ΔV = 6.82- 2.45 = 4.37 L
we have Pressur P= 3.22 atm
workdone . W =-( 3.22 * 4.37 )= -14.0714 L.atm
1 liter atmosphere = 101.325 joules
Therefore, 14.07 L atm = (101.325 * 14.07) = 1425.643 J
P-V work invovled is -14.07 L.atm ( or -1425.643 J)
Negative sign indicates workdone by the system.(gas transferred energy to surrounding)
The P-V work is given by P×∆V
= Pressure×(final volume - initial volume)
=3.22×(6.82-2.45)L.atm
=14.07L.atm
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