Question

A mysterious rocket-propelled object of mass 44.0 kg is initially at rest in the middle of the horizontal, frictionless surface of an ice-covered lake. Then a force directed east and with magnitude F(t)= (16.0 N/s )t is applied.

Part A

How far does the object travel in the first 6.00 s after the force is applied?

Express your answer with the appropriate units.

I got x=39.24 meters and i was sure that was correct, pleas help me understand why its not :)

Answer 1

given F = 16 t

as F = ma

ma = 16 t

a = 16t/44 = 0.3636 t

intigrating a with time gives int F dt = Velocity

V (t) = intg adt = 0.3636t^2 /2

intgrating again Vdt gives the distance travelleld

as S(t) = 0.3636 t^3/6

S = 0.3636* 6*6*6/6

S = 13.08 m ------------<<<<<<<<<Answer