apply force F = ma
so accleration a = F./m
a = 15.6/40
a = 0.39 m/s^2
now use the kinematic equation S = 0.5 at^2
S = 0.5 * 0.39 * 4.75 *4.75
S = x = 4.4 m
a = F/m = 15.6t/40.0 =
a = 0.39 t
Velocity after time t1 = int(a*dt)
= 0.39/2 *t^2 = 0.195t^2
Distance covered = int(vdt)]t=0,4.75
= 0.195t^3 /3
= 6.966 m
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