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For the next two problems use the following information: A simply supported Douglas fir wood beam is designed to carry a concentrated load P of 1250 lbr in the center. The distance L between supports is 96 inches. For the beam cross sectional area given below, determine the moment of inertia and deflection. Douglas fir has the following properties: Modulus of Elasticity 1.76 x 100 psi, Density 34 lbm/ff3 Beam dimensions are: Web thickness tw 0.875 in, flange thickness t 1.25 in., web width w 5 in., flange height h 7.50 in, total beam length L total 120 in. tw 17) L total 48. (4 points) Moment of inertia for the beam is: a. 194.66 int b. 142.51 in c. 106.88 in d. 97.33 in 88.18 in 49. (4 points) Deflection of the beam at the mid-point (center) of the span is: a. 0.090 in (b )0.148 in 0.290 in d. 0.179 in e. 0.38 in

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l2 2 P L 4862 丨9.50)(96 X1

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