Question

A current of 2.20 A is flowing through a 1000-turn solenoid of length L = 35.0 cm. What is the magnitude of the magnetic field inside the solenoid? If this solenoid perfect one, i.e. the turns are perpendicular with axis the solenoid (90 degree), the angle from turns to axis is 5 degree the magnitude of the magnetic field inside of the solenoid?

Answer 1

for ideal solenoid

B= $\mu ni$

where n is number of coil per unit length

B= 4*3.14*10^-7 * (1000/.35)*2.20

=7.89 $\mu T$ ans

IN Case of imperfect solenoid

B= $\mu ni cos\theta$= 7.89 * cos (5) = 7.85 $\mu T$   ans