A 3.0 amp current flowing through a solenoid, length 2.5 cm, produces a magnetic flux density in the air-filled core of 6.0 mT. How many complete turns of wire make up the solenoid?
magnetic field inside the solenoid is
B =mu*n*I
=mu*(N/L)*I
B*L=mu*N*I
N =(B*L)/(mu*I)
= (6*10^-3 T*0.025 m)/(4pi*10^-7*3 A)
= 39.7887 turns
= 39 turns
A 3.0 amp current flowing through a solenoid, length 2.5 cm, produces a magnetic flux density...
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