P: x+2y 10 Р2: -х-2у +z-1 (a) Do they intersect? (b) If so, find the equation...
Find the basis function of the differential equation using Frobenius method. b. 2у"+ (1— 2г)y+ (ӕ- 1)у %3D0 c. ()y"(4x 2)y' +2y 0 b. 2у"+ (1— 2г)y+ (ӕ- 1)у %3D0 c. ()y"(4x 2)y' +2y 0
Question 12 Find parametric equations for the line of intersection of the planes - 2y+z= 1 and 2x + y - 3x = -3. Does the line L intersect the plane 2x - y - 3x = 1? If so, at what point? Note: This is the review exercise at the end of Lecture 2.
The graphs of the surfaces z=(x²+y²)² and z=3-2 x²-2 y² intersect in 3D-Space. Find an equation for the projection of this intersection in the x y-plane.
The equation z - x ^ 2- 2y ^ 2 + 2x - 4y - 2 = 0 is given. Surface: a) Explore the type of the intersection curve with the z = 0 plane and draw it. b) Find the tangent plane and normal line at point (0,0,2).
Determine whether the given lines intersect. If so, find the point of intersection. (If not, enter NOT.) x = 6 + t, y = 3 + t, z = -1 + 2t x = 8 + 2s, y = 9+ 4s, z = -3 + S (x, y, z) = eBook
Find the line of intersection of the planes x + 2y + z = 9 and x - 2y + 3z = 13. x = -4t+ 7, y = and z = 2t + 2 x= -4t+9, y = 1 and z = 2t + 2 x = 4t + 7, y = tand z = 2t +2 x = -4t+ 7, y = ? and z = 2t - 2
Х (x+2y = 20 -3x+2y's 4 ²12 X²0 yzo Find the point of intersection - Shade the region that satisfies the system of inequality
Given a second order linear homogeneous differential equation а2(х)у" + а (х)У + аo(х)у — 0 we know that a fundamental set for this ODE consists of a pair linearly independent solutions yı, V2. But there are times when only one function, call it y, is available and we would like to find a second linearly independent solution. We can find y2 using the method of reduction of order. First, under the necessary assumption the a2(x) F 0 we rewrite...
Find the line of intersection of the planes x + 2y + z = 7 and x - 2y + 3z = 13. x = 4t+4, y = t and z = 2t + 3 x=-4t+4, y = t and z= 2t-3 x=-4t+ 7, y=t and z= 2t + 3 x=-4t +4, y = t and z = 2t + 3
TOTAL MARKS: 25 QUESTION 4 (a) Find a normal vector and an equation for the tangent plane to the surface at the point P: (-2,1,3). Determine the equation of the line formed by the intersection of this plane with the plane z = 0. 10 marks (b) Find the directional derivative of the function F(r, y, z)at the point P: (1,-1,-2) in the direction of the vector Give a brief interpretation of what your result means. 2y -3 [9 marks]...