2. Electrons move through a magnetic field of 3.0x10-3T balanced by an electric field of 2.4x10'...
Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.25 T.Part (a) What is the potential difference, in volts, required in the first part of the experiment to accelerate electrons to a speed of 5.95 x 107 m/s?Part (b) Find the radius of curvature, in meters, of the path of a proton accelerated through this same potential...
A proton enters a region of constant magnetic field, perpendicular to the field and after being accelerated from rest by an electric field through an electrical potential difference of 470 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 22 cm. 1.42e-3 How can you determine the speed at which the proton enters the region of constant magnetic field? What force provides the centripetal force that causes the proton...
In a laboratory experiment, a beam of electrons is accelerated from rest through a 148-V potential difference. The beam then enters a uniform magnetic field and follows a circular path of radius r = 19.1 cm in the field region. (a) What is the angle between the magnetic field and the electrons' velocity? (b) What is the magnitude of the magnetic field? Submit Answer
charged gold for charged metal plates I Figure 9. Investigating the electric field between two charged metal plates 1 Figure 9.5 on page 134 shows apparatus used to investigate the field between a pair of charged, parallel plates. a Explain why the piece of gold foil deflects in the manner shown. b State and explain what would be observed if the gold foil momentarily touched the negatively charged plate. 2 A charged dust particle in an electric field experiences a...
A proton enters a region of constant magnetic field, perpendioular to the field and after being accelerated from rest by an electric fneld through an electrical potential difference of 360 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with radius of 30 cm. Addiional Materials
A proton enters a region of constant magnetic field, perpendicular to the fie and after being accelerated from rest by an electric field through an electric potential difference of - 350 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 21 cm. mt As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will...
A 0.342 T magnetic field in a mass spectrometer causes an isotope of sodium to move in a circular path with a radius of 0.049 m. The charge on an ion is 1.60218 × 10−19 C. If the ions are moving with a speed of 11800 m/s, what is the isotope’s mass? Answer in units of kg.
A scanning electron microscope uses a uniform 15.0-kN/C electric field to accelerate electrons horizontally toward the subject to be imaged. After travelling 5.0 cmthe electrons are accelerated to a speed of 1.62x107m/s. The next step is to deflect the electrons so that they can scan across the sample—hence the scanning electron microscope. To accomplish this, the electrons are directed between a pair of oppositely charged parallel plates, which produce a uniform electric field of 6.42x103N/C perpendicular to the electron beam....
ULINIL In a laboratory experiment, a beam of electrons is accelerated from rest through a 124-V potential difference. The beam then enters a uniform magnetic field and follows a circular path of radius r = 17.3 cm in the field region. (a) What is the angle between the magnetic field and the electrons' velocity? 90 (b) What is the magnitude of the magnetic field? IT Entra sumber Submit Answer Viewing Saved Work Revert to Last Response View Next Question
A charged particle is outside of a fixed magnetic field. It is moving in a straight line, accelerating from rest through a potential difference V. When it enters the magnetic field, the particle's path is oriented perpendicular to the magnetic field. The magnetic field deflects the particle into a circular arc of radius R. If the accelerating potential is doubled to 2V, what will be the radius of the circular arc? Express your answer in terms of multiples of R....