Question

1. The thermal decomposition of isopropyl isocyanate was studied in a differential packed-bed reactor. From the data in Table 1, determine the reaction-rate-law parameters. Table 1. Raw Datat Run 1 Rate (mol/s.dm) 4.9 x 10° 1.1 x 10" 2 .4 x 10 2 .2 x 10? 11.18 x 10 1.82 x 102 Concentration Temperature (mol/dm') -(K) 0.2 700 0.02 750 0.05 800 0.08 850 0. 1 900 0.06 1950 3 4 6 1 Jofostan Journal of Chemical Engineering, Vol. 15, page 743(1995).

Answer 1

Rate	CA	ln(rate)	ln(CA)
0.00049	0.2	-7.6211052	-1.6094379
0.00011	0.02	-9.1150302	-3.912023
0.0024	0.05	-6.0322865	-2.9957323
0.022	0.08	-3.8167128	-2.5257286
0.118	0.1	-2.1370707	-2.3025851
0.0182	0.06	-4.0063337	-2.8134107

Chart Title -4.5 4 35 -3 -25 -1.5 -1 -0. 5 0 y= 1.2503x - 2.0875

From graph

y = 1.2503x - 2.0875

n=1.2503

ln(k)=-2.0875

k=exp(-2.0875)=0.124