Question

I need 4 and 6 and show all work please

4) A 5 cm tall object is placed in front 20 cm. The object is located 20 cm from the spherical mirror of a spherical mirror with a radius of curvature of - a) What is the object distance? b) What is the image distance? c) What is the focal length? d) What is the size of the object? e) What is the size of the image? 1) What is the nature of the image (Rear or Virtual)? g) What is the Magnification? h) What is the orientation of the image (Erect or Inverted) i) Where is the image located? 5) An Object is 4 times as big as the image formed by a concave 30 cm radius of curvature. (10 points) spherical mirror with a a) What is the object distance? b) What is the image distance? c) What is the focal length? d) What is the size of the object? e) What is the size of the image? f) What is the nature of the image (Real or Virtual)? g) What is the Magnification? h) What is the orientation of the image (Erect or Inverted)? i) Where is the image located? 6) A 10 cm tall object is placed 25 cm in front of a diverging lens with a focal length of 15 cm. (10 points) a) What is the object distance? b) What is the image distance? c) What is the focal length? d) What is the size of the object? e) What is the size of the image? f) What is the nature of the image (Real or Virtual)? g) What is the Magnification? h) What is the orientation of the image (Erect or Inverted)? i) Where is the image located?

Answer 1

Spherical mirror is not specified in equation so we assume spherical mirror is concave mirror Note: - we use co ordinate joint by sign constructions for solving problems distance of objects (4) = 20 cm distance of a marge (U) = -20 cm because with object placed at center of curves a mark also forall at center of curvature focal length 1/f = 1/V + 1/u = 1/-20 + 1/-20 = -1 - 1/20 1/f = -2/20 = -1/10 = > f = -10 cm size of object (given h = 5 cm size of image h' = 5 cm rightarrow becomes at center of curvature image formed force same size as object image formed due to real rays inter section after reflect so rightarrow real image magnification M = height of image (h)/height of object (h) = 5/5 = 1 image below principle as is rightarrow inverted location of image 20 cm from pole R = -30 cm let size of image (f) = x than size