Question

4. A 10 foot conical tank with a radius 5 feet is filled with oil weighing 57 pounds/ft? (a)-(c): Do not integrate. Just set up the integral so that I can see the differences in each expression. (a) Set up the integral to find the work to pump the oil to the top of the tank. (b) Set up the integral to find the work to lift the top 3 feet of olive oil over the top of the tank. (c) Set up the integral to find the work to raise the oil to the top of 1 foot height straw.

Answer 1

weight density of oil wa s7 lb ft Arrume a stice loft h varies from (0, 10) of radius or at h height below the top tanda 5 - 7 / 2 area of slice A a volume of the tand = 5 -Ito (r= h rt = 1 h a that Ava Asha The on the IN weight of slice owa w.ava 57h2 sn le _ work done to left the tice 'l above to pump out one, the top is ow a swih - 57 ah shin total work done to pumpout whole oil ones the top of tank setup wa la espera hºon - am (*)' ut som at 10000) => [35625*). (6) work to lift the top 3 ft of olive oil over the top h varies from 0 to 3 so total work done Jo to the top of 1 foot work height to raise the oil straw 1411 I has work done to lift the tice hith' height to to pump out AW. AwCnH2= S7k h²an lhtly 4 total work done wa I s 57R h²cht da hchallan

force applied to stretch the spring og en F, e kx. work done we | Exdo work done to stretch the spring from 3tim to (a) 44 cm 0144 0+44 I ka do kx2 = 2 044 334 E r 1 01442 - 0.342) = 2 K = 4 51.282 0.442 -0.24² 0.078 by the spring work is needed to shatch 0.44 m to 0.64m. from 0.44 dega (01642 -0942) 554] 010