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Question #01 (30 points) Consider the following circuit. Let us define the phasors in terms of the Sine function. 0.25 F 12 H

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Answer #1

хе, XL Xenon ten vissink +30) V s sin(2t + 30 ) HAA XL2 (30° volta W m I.. ķ Voits XL = WL, XL = 2x12 = 24 h XL2 = W X L2 =2x22 +326 o 22 + 2b = 0 384+j23.92 2+2a = 2-384 + 2+2a & Zc (122+70) x (2+za) ze = 2e + (22+2b) +@+20) Zeq = -a + 23472 (3:45 zWRIT I ()= r2 x 20435 sin (24 +50.190) r time exp T ict) 12x20435 sin (2+ +10-18)A 3.141 see V(A) & sin (2++30)v 30141 see 3

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