The angle of a prism is 60° in the angle of minimum deviation is 56.5°, what will be the refractive index of the prism?
a. 1.5
b. 1.7
c. 1.6
d. 1.55
Relation between refractive index of prism and angle of miniumu deviation is given by:
n = [sin ((A + D)/2)]/sin (A/2)
A = Angle of prism = 60 deg
D = Angle of deviation = 56.5 deg
So,
A/2 = 30 deg
(A + D)/2 = (60 + 56.5)/2 = 58.25 deg
So,
n = sin 58.25 deg/sin 30 deg
n = 1.7
Correct option is B.
Let me know if you've any query.
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