Question

Question 11 5 pts Assume that the weight of quarters are normally distributed with a man of 5.67g and a standard deviation of 0.07g. Find the probability that the next quarter you pick up weighs between 5.485 and 582. (Hint: Start by finding 2-scores! Answer to 4 decimal places 0.9806 Question 12 4 pts The serum cholesterol levels for men in one age group are normally distributed with a mean of 1782 and a standard deviation of 90.. Find the third quartila (cholesterol level where 75% of the area is to the left of that number.) Units are mg/100 ml. Answer to the nearest tenth Show work on your paper 205.71 Question 13 13 pts The number of loaves of rye bread left on the shelf of a local bakery at the end of the day is denoted by the random variable X. Past records show that the probability distribution of is shown in the table: X TO 1 2 3 4 5 16 PX - 0.20 025 0.20 0.15 10.10 10.08 0.02 aj Find the probability that there will be at least 3 loaves left at the end of the day Answer to two decimal places b) Find the expected number of loaves of rye bread left at the end of the day. Use the formula for the mean of a discrete random variable Answer to two decimo c) Find the standard deviation Show all work! Use the formula for a discrete random variabe, Awwer to three decimal places

question 11, 12 and 13 thanks on advance!

Answer 1

=P[5-48 5 25.82] = P[A45.82] - P[X25-48] 11. Let, & denates the weight of quarter. (in gom). XvN/M = 5.67, oh 0.072) Y = X-5.67 UN(0, 1) :P[X sx] = P [Y 2 X-5.67] =(2567) (90):C0f of race. P(x) + 2 (-x) = 2 and 582 gm] o not 0.07 2. Po [ weightbetween 5-18 gm & 5-82-567) 0.07 0.07 & ( 5:48-54 567) P(2.40) – (-2-71) - 0 (3.14) + (2-71) - 1 50-9966358 + 0-9838326-1 -0.9805 lapprimately) Here § (2) is calculated table abridged from a Biometrika Tables for statisticians". (stry) asing 12) det, x duptes the secum Cholesterol levels, for men. (mg/100mL). XNN (U=178 2,0 0340189). ry ..Y=x-1782 UN(0,1). P[XS XJ = P[ Ysx-2782] 40.86 Let, be the third quartile of x. - (x - 178.2 HA) 40-8 dy 3/4

17. А. Чо• 8 - 10-15 - ц - Ф(617) – 07857 2)-2(461) ЛАМ, -) 18- - о67 400

1934 205-636 Cappese) mg / m2 X 3 45 6 of Total Third quartile 23. Let, & denotes the number of loaves left at the end of the P[X= 0.20 0.25 0.20 0.15 0.10 0.08 0.02 E PLAY (a) Pe[At least 3 loaves left at the end of the day varıx) = f(x) - E(X) = 6-78-(2002) = 2:6396 205.636 day. I .2 P[X3] - 1-P[x<3 ]=1-[P[x=03 + P[=1] youturo +P[x=2] - 1-0.65 = 0.35 (thry) (b)f(x): 3 x-P[x=x] = Of 0.25 + +0:20*2)+(0-4543) 7(0-1024) + (0.08x5) +(0.0246) - 2:02 AM (e) E(X) = * *px=]€ 0+0:25 +10-2014)+(0-45~9) 40-10-16)+(0-08X85) + (0.02x36) - 6.72. vaz(x) 1.625 Capbwow) (Ang) 6 x=0 Line x=0 . SD(A) =