w1 x1 = w2 x2
given
x1 = 5 ft
w1 = 90 lb
w2 = 125 lb
putting the values
90 * 5 = 125 * x2
thus x2 = 450 / 125
= 3.6 ft from the fulcrum
The figure shows a lever system, similar to a seesaw that you might find in a...
Need help with part C. Thank you! This is the figure above. However, it has different values than the homework question above. PRACTICE IT Use the worked example above to help you solve this problem. A woman of mass m = 53.6 kg sits on the left end of a seesaw-a plank of length L = 4.39 m, pivoted in the middle as shown in the figure. (a) First compute the torques on the seesaw about an axis that passes...