Given these equations SO_2(g) rightarrow O_2(g)+ S(s) DeltaHdegree = +300 kJ 2SO_2(g) + O_2(g) rightarrow 2SO_3(g)...

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Answer 1

Answer #1

$\Delta H^{o}$ [SO2] = 300KJ

$\Delta H^{o}$ [SO3] = -200KJ

$\Delta H^{o}_{f}$ = $\Delta H^{o}$ [produc] - $\Delta H^{o}$ [reactant]

$\Delta H^{o}_{f}$ = $\Delta H^{o}$ [SO3] - $\Delta H^{o}$ [SO2]

$\Delta H^{o}_{f}$ = -200 - 300 = - 500 KJ/mol

Option A is the right Answer.

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Answer 2

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