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3. The average weight of 80 randomly selected potatoe chip packages is 98.5gm. Historically the package weights have a standa

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Answer #1

solution:

given

\mu = 100

\sigma = 5.3

n = 80

To find P(T < 98.5):

=p(T-\mu/\sigma /n<98.5-100/ 5.3/00)

=p(z<-1.5/0.592558)

=p(z<-2.5313)

=1-p(z<2.5313)

=1-0.9943(from table)

=0.0057

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