Question

k110 9 +5=14 -4 n-3=-11 8 17-3 C) 10-8=-24 3 nd 9、 the (L) The quotient of a number and-7, decreased by 2, is 10. Find the number.

Answer 1

Answer: (J) k=99, (V) m=-36, (H) n=-64, (O) w=100, (T) x=-48, (E) a=160 and (L) Number is -84.

Explanation:

(J)

$\frac{k}{9}-1=10$

$\frac{k}{9}-1+1=10+1$

$\frac{k}{9}=11$

$9\times \frac{k}{9}=9\times 11$

$k=99$

(V)

$\frac{m}{-4}+5=14$

$\frac{m}{-4}+5-5=14-5$

$\frac{m}{-4}=9$

$-4\times \frac{m}{-4}=-4\times 9$

$m=-36$

(H)

$\frac{n}{8}-3=-11$

$\frac{n}{8}-3+3=-11+3$

$\frac{n}{8}=-8$

$8\times \frac{n}{8}=8\times (-8)$

$n=-64$

(O)

$\frac{w}{-5}+17=-3$

$\frac{w}{-5}+17-17=-3-17$

$\frac{w}{-5}=-20$

$-5\times (\frac{w}{-5})=-5\times (-20)$

$w=100$

(T)

$\frac{-x}{3}+4=20$

$\frac{-x}{3}+4-4=20-4$

$\frac{-x}{3}=16$

$-3\times \frac{-x}{3}=-3\times 16$

$x=-48$

(E)

$\frac{-a}{10}-8=-24$

$\frac{-a}{10}-8+8=-24+8$

$\frac{-a}{10}=-16$

$-10\times \frac{-a}{10}=-10\times -16$

$a=160$

(L)

Let the number be x. So,

$\frac{x}{-7}-2=10$

$\frac{x}{-7}-2+2=10+2$

$\frac{x}{-7}=12$

$-7\times \frac{x}{-7}=-7\times 12$

$x=-84$

So, the number is -84.