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how to do the part II
The weights of cans of Ocean brand tuna are supposed...
1 point The weights of cans of Ocean brand tuna are supposed to have a net...
1 point The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 6.03 ounces and a standard deviation of 0.23 ounces. Suppose that you draw a random sample of 43 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the probability that the mean weight...
The weights of cans of Ocean brand tuna are supposed to have a net weight of...
The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 6.01 ounces and a standard deviation of 0.22 ounces. Suppose that you draw a random sample of 30 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the probability that the mean weight of the...
us ProblemProblem List Next Problem (1 point) The weights of cans of Ocean brand tuna are...
us ProblemProblem List Next Problem (1 point) The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.22 ounces. Suppose that you draw a random sample of 43 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the...
Suppose the scores of students on an exam are Normally distributed with a mean of 303...
Suppose the scores of students on an exam are Normally distributed with a mean of 303 and a standard deviation of 39. Then approximately 99.7% of the exam scores lie between the numbers and such that the mean is halfway between these two integers. (You are not to use Rcmdr for this question.) answer: answer: the weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight...
The manufacturer of cans of salmon that are supposed to have a net weight of 6...
The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.1 ounces and a standard deviation of 0.22 ounce. Suppose that you draw a random sample of 26 cans. Find the probability that the mean weight of the sample is less than 6.09 ounces. Probability =
(1 point) The manufacturer of cans of salmon that are supposed to have a net weight...
(1 point) The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.19 ounces and a standard deviation of 0.23 ounce. Suppose that you draw a random sample of 37 cans. Find the probability that the mean weight of the sample is less than 6.14 ounces. Probability =
How much is in that can? A machine that fills beverage cans is supposed to put...
How much is in that can? A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. Followin are the amounts measured in a simple random sample of eight cans. 12.09 11.98 12.16 12.03 12.12 12.20 12.10 12.18 Send data to Excel Perform a hypothesis test to determine whether the mean volume differs from 12 ounces. Use the a=0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part 1 of...
help solve The average fill volume for a soda company's cans is supposed to be 16...
help solve
The average fill volume for a soda company's cans is supposed to be 16 ounces. The filling machine has a known standard deviation of 0.14 ounces. Each week, the company selects a simple random sample of 30 cans and carefully measures the volume in each can. The results are provided in the accompanying table. Based on the data in the sample, what would you conclude about whether the filling process is working as expected? Base your answer on...
please anwser the following question below there are 3 separatw part to rhis one question Assume...
please anwser the following question below there are 3
separatw part to rhis one question
Assume that cans o cola are filed such that the actual amounts have a population mean of μ 12.00 ounces. A random sample of 36 cans has a mean amour t of 12.27 ounces. The distribution of sample means of size n-36 is normal with an assumed mean of 12.00 ounces, and those sample means have a standard deviation of 0.04 ounce. Complete parts (a)...
A sample of 14 small bags of the same brand of candies was selected. Assume that...
A sample of 14 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was 3 ounces with a standard deviation of 0.15 ounces. The population standard deviation is known to be 0.1 ounce. NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that...
1 point The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 6.03 ounces and a standard deviation of 0.23 ounces. Suppose that you draw a random sample of 43 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the probability that the mean weight...
us ProblemProblem List Next Problem (1 point) The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.22 ounces. Suppose that you draw a random sample of 43 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the...
(1 point) The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.19 ounces and a standard deviation of 0.23 ounce. Suppose that you draw a random sample of 37 cans. Find the probability that the mean weight of the sample is less than 6.14 ounces. Probability =
How much is in that can? A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. Followin are the amounts measured in a simple random sample of eight cans. 12.09 11.98 12.16 12.03 12.12 12.20 12.10 12.18 Send data to Excel Perform a hypothesis test to determine whether the mean volume differs from 12 ounces. Use the a=0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part 1 of...
help solve
The average fill volume for a soda company's cans is supposed to be 16 ounces. The filling machine has a known standard deviation of 0.14 ounces. Each week, the company selects a simple random sample of 30 cans and carefully measures the volume in each can. The results are provided in the accompanying table. Based on the data in the sample, what would you conclude about whether the filling process is working as expected? Base your answer on...
please anwser the following question below there are 3
separatw part to rhis one question
Assume that cans o cola are filed such that the actual amounts have a population mean of μ 12.00 ounces. A random sample of 36 cans has a mean amour t of 12.27 ounces. The distribution of sample means of size n-36 is normal with an assumed mean of 12.00 ounces, and those sample means have a standard deviation of 0.04 ounce. Complete parts (a)...
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