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1 point The weights of cans of Ocean brand tuna are supposed to have a net...
The weights of cans of Ocean brand tuna are supposed to have a net weight of...
The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 6.01 ounces and a standard deviation of 0.22 ounces. Suppose that you draw a random sample of 30 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the probability that the mean weight of the...
how to do the part II The weights of cans of Ocean brand tuna are supposed...
how to do the part II
The weights of cans of Ocean brand tuna are supposed to have a net weight of 6.0 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 6.01 ounces and a standard deviation of 0.21 ounces. Suppose that you draw a random sample of 34 such cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, Åfind the...
us ProblemProblem List Next Problem (1 point) The weights of cans of Ocean brand tuna are...
us ProblemProblem List Next Problem (1 point) The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.22 ounces. Suppose that you draw a random sample of 43 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the...
(1 point) The manufacturer of cans of salmon that are supposed to have a net weight...
(1 point) The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.19 ounces and a standard deviation of 0.23 ounce. Suppose that you draw a random sample of 37 cans. Find the probability that the mean weight of the sample is less than 6.14 ounces. Probability =
Suppose the scores of students on an exam are Normally distributed with a mean of 303...
Suppose the scores of students on an exam are Normally distributed with a mean of 303 and a standard deviation of 39. Then approximately 99.7% of the exam scores lie between the numbers and such that the mean is halfway between these two integers. (You are not to use Rcmdr for this question.) answer: answer: the weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight...
The manufacturer of cans of salmon that are supposed to have a net weight of 6...
The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.1 ounces and a standard deviation of 0.22 ounce. Suppose that you draw a random sample of 26 cans. Find the probability that the mean weight of the sample is less than 6.09 ounces. Probability =
Cans of salmon are supposed to have a net weight of 6 oz. The canner says...
Cans of salmon are supposed to have a net weight of 6 oz. The canner says that the net weight is a random variable with mean μ-6.05 oz. and stand, dev. σ-0.18 oz. Suppose you take a random sample of 36 cans and calculate the sample mean weight to be 5.97 oz. What is the probabity that the mean weight of the sample is less than or equal to 5.97 oz?
How much is in that can? A machine that fills beverage cans is supposed to put...
How much is in that can? A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. Followin are the amounts measured in a simple random sample of eight cans. 12.09 11.98 12.16 12.03 12.12 12.20 12.10 12.18 Send data to Excel Perform a hypothesis test to determine whether the mean volume differs from 12 ounces. Use the a=0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part 1 of...
Assume that cans of cola are filled such that the actual amounts have a population mean...
Assume that cans of cola are filled such that the actual amounts have a population mean of muequals20.00 ounces. A random sample of 36 cans has a mean amount of 20.33 ounces. The distribution of sample means of size nequals36 is normal with an assumed mean of 20.00 ounces, and those sample means have a standard deviation of 0.04 ounce. Complete parts (a) through (c) below. what is the standard deviation is the sample mean away from the mean of...
Soft drink cans are filled by an automated filling machine and the standard deviation is 0.5...
Soft drink cans are filled by an automated filling machine and the standard deviation is 0.5 fluid ounce. Assume that the fill volumes of the cans are independent, normal random variables. Round your answers to four decimal places (e.g. 98.7654). What is the standard deviation of the average fill volume of 100 cans? If the mean fill volume 12.1 ounces, what is the probability that the average fill volume of the 100 cans is less than 12 fluid ounces? What...
how to do the part II
The weights of cans of Ocean brand tuna are supposed to have a net weight of 6.0 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 6.01 ounces and a standard deviation of 0.21 ounces. Suppose that you draw a random sample of 34 such cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, Åfind the...
us ProblemProblem List Next Problem (1 point) The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.22 ounces. Suppose that you draw a random sample of 43 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the...
(1 point) The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.19 ounces and a standard deviation of 0.23 ounce. Suppose that you draw a random sample of 37 cans. Find the probability that the mean weight of the sample is less than 6.14 ounces. Probability =
Cans of salmon are supposed to have a net weight of 6 oz. The canner says that the net weight is a random variable with mean μ-6.05 oz. and stand, dev. σ-0.18 oz. Suppose you take a random sample of 36 cans and calculate the sample mean weight to be 5.97 oz. What is the probabity that the mean weight of the sample is less than or equal to 5.97 oz?
How much is in that can? A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. Followin are the amounts measured in a simple random sample of eight cans. 12.09 11.98 12.16 12.03 12.12 12.20 12.10 12.18 Send data to Excel Perform a hypothesis test to determine whether the mean volume differs from 12 ounces. Use the a=0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part 1 of...
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