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1) A 0.99 kg block of wood is attached to a spring whose spring constant, k...
5. A bullet of mass m-0.02 kg was horizontally shot into a wood block of mass...
5. A bullet of mass m-0.02 kg was horizontally shot into a wood block of mass mo 8.98 kg, which is attached at one end of a spring with a spring constant k = 100 N/m, as shown in right Figure. After the bullet was embedded into the wood block, the spring was compressed 10 cm. If the coefficient of kinetic friction is 0.2 between the wood block and the surface, find the initial velocity of the bullet. (10 points)
10. A 0.600-kg wood block is firmly attached to a very light horizontal spring k 200...
10. A 0.600-kg wood block is firmly attached to a very light horizontal spring k 200 N/m as shown in the figure. It is noted that the block-spring system, when compressed 5.00 cm and released, stretches out 4.00 cm beyond the equilibrium position before stopping and turning back. What is the coefficient of kinetic friction between the block and the table?
wooden block with mass M 3 kg is lying on a horizontal table and is attached to a spring in its equilibrium position. It is hit by a bullet with mass m 5 g which moves horizontally. The bullet re...
wooden block with mass M 3 kg is lying on a horizontal table and is attached to a spring in its equilibrium position. It is hit by a bullet with mass m 5 g which moves horizontally. The bullet remains in the block after colliding with it. The block moves on the table compressing the spring, with spring constant k 50 Nm, a distance 10 cm. The coefficient of kinetic friction uk 0.2. a) Find the elastic energy stored in...
Ballistic and Springs-- An 8g bullet is shot into a 2.2-kg block of wood thatis initially...
Ballistic and Springs-- An 8g bullet is shot into a 2.2-kg block of wood thatis initially at rest. The bullet embeds in the block, and together they slide on a horizontal frictionless surface at 1.2 m/s towards on unstrained ideal spring that is fixed to a wall. The spring is compressed by the block as it comes to a momentary stop. Ignore the effects of air resistance. (a) What is the velocity of the bullet immediately before it hits the...
A block of mass m = 3.5 kg is attached to a spring with spring constant...
A block of mass m = 3.5 kg is attached to a spring with spring constant k = 520 N/m. It is initially at rest on an inclined plane that is at an angle of θ = 21° with respect to the horizontal, and the coefficient of kinetic friction between the block and the plane is μk = 0.16. In the initial position, where the spring is compressed by a distance of d = 0.14 m, the mass is at...
A 10.0-g bullet is fired into, and embeds itself in, a 1.95-kg block attached to a...
A 10.0-g bullet is fired into, and embeds itself in, a 1.95-kg block attached to a spring with a force constant of 20.0 N/m and whose mass is negligible. How far is the spring compressed if the bullet has a speed of 300 m/s just before it strikes the block and the block slides on a frictionless surface? Note: You must use conservation of momentum in this problem because of the inelastic collision between the bullet and block.
A 10.0-g bullet is fired into, and embeds itself in, a 1.80-kg block attached to a...
A 10.0-g bullet is fired into, and embeds itself in, a 1.80-kg block attached to a spring with a force constant of 22.3 N/m and whose mass is negligible. How far is the spring compressed if the bullet has a speed of 300 m/s just before it strikes the block and the block slides on a frictionless surface? Note: You must use conservation of momentum in this problem because of the inelastic collision between the bullet and block.
A block of mass m = 4.5 kg is attached to a spring with spring constant k = 710 N/m.
A block of mass m = 4.5 kg is attached to a spring with spring constant k = 710 N/m. It is initially at rest on an inclined plane that is at an angle of θ = 25° with respect to the horizontal, and the coefficient of kinetic friction between the block and the plane is μk=0.18. In the initial position, where the spring is compressed by a distance of d = 0.12 m, the mass is at its lowest...
A block of mass m = 3.5 kg is attached to a spring with spring constant k = 780 N/m
A block of mass m = 3.5 kg is attached to a spring with spring constant k = 780 N/m. It is initially at rest on an inclined plane that is at an angle of θ = 28° with respect to the horizontal, and the coefficient of kinetic friction between the block and the plane is μk = 0.19. In the initial position, where the spring is compressed by a distance of d = 0.19 m, the mass is at...
A 9.0 g bullet is fired into a 8.0 kg wood block that is at rest...
A 9.0 g bullet is fired into a 8.0 kg wood block that is at rest on a wood table. The block, with the bullet embedded, slides 5.0 cm across the table. The coefficient of kinetic friction for wood sliding on wood is 0.20. What was the speed of the bullet?
5. A bullet of mass m-0.02 kg was horizontally shot into a wood block of mass mo 8.98 kg, which is attached at one end of a spring with a spring constant k = 100 N/m, as shown in right Figure. After the bullet was embedded into the wood block, the spring was compressed 10 cm. If the coefficient of kinetic friction is 0.2 between the wood block and the surface, find the initial velocity of the bullet. (10 points)
10. A 0.600-kg wood block is firmly attached to a very light horizontal spring k 200 N/m as shown in the figure. It is noted that the block-spring system, when compressed 5.00 cm and released, stretches out 4.00 cm beyond the equilibrium position before stopping and turning back. What is the coefficient of kinetic friction between the block and the table?
wooden block with mass M 3 kg is lying on a horizontal table and is attached to a spring in its equilibrium position. It is hit by a bullet with mass m 5 g which moves horizontally. The bullet remains in the block after colliding with it. The block moves on the table compressing the spring, with spring constant k 50 Nm, a distance 10 cm. The coefficient of kinetic friction uk 0.2. a) Find the elastic energy stored in...
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Amplitude=3;
fs=8000;
n=0:399;
t=0:1/fs: n*1/fs-1/fs;
signal=3+3*cos(2*pi*1100*t)+3*cos(2*pi*2200*t)+3*cos(2*pi*3300*t);
fftSignal= fft(signal);
fftSignal=f ftshift (fftSignal);
f=fs/2*linspace(-1,1,fs);
plot(f,abs(fftsignal);
xlabel('Frequency(Hz)’)
yla
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