Question

D AC CIRCUITS PHY-2054 TEST 2 Student's Name: Williams Date o let) You must show must show major calculation steps and insert the results after approximating them in the corresponding boxes orresponding boxes. No single number answers will be credited 1). You are given the data shown below for an RCL series AC circuit, R108 ohm; 1082 L-0.112 H; C= 15.0 F-0.0000150 F: V -110 volt; -250 Hz CALCULATE (with 6 significant figures): 6-2x, XL: Xc:(XL-Xc); Z; L i tano, o, coso, the power P, and the resonant frequency for the L and C values given. (Please insert answers in the Table below and include the correct units when applicable) (30 pts) Show calculations below:(use back if needed) 2110 Vrms 250 Hz 15.0 uF A) w = 2 If = 16 Variable Value |(units) 0-2 XL 1663 182.147n Xc XL-Xc | Ims tan coso Power Fresonant

Answer 1

Sof!Given :- f = 250 H2, v . 110v. c=1spf., L= 0.112 H. R = 1082 10 w = 20 f = 2x3.14150x250 T: 3.141 sa w= 6 15 70.79. sad sol significant figures au we can unite we isto.79. had sol X2= 21 fL . x = 2x3.14 X 250 0.112 X2= 175.8 ur au 6 significant figures. [ X: . 175.840 s

ANA X बाद Xc 2x3.14 X250X0.000000 * @ » - - 08. 6 4 0 - 4 2. L8) » Xu-Yo = 133.377 2 ® (fempedence) SR(XI-X fro@)*7 (133.377) 1981.619.12. 6 Imus is giuen by. I ruus mus 110 This = 121.6i : 0.640954. A. I nus 0.640954 AT

o tan = (x2-x) 1 = tan &= (1915.840 - 42.46 28) I lain = 1.23497.1 lo 8 6 from above calculation, tan a = 1.23497 a= tant (1.23497) 19. 51.0016 0. 6 from east calculalian, cos Q = cos (51.0016) 27 I cos a= 0.6.29 298 you can abo calculate by Cosa = /

Cosg=. 108 171.619 - = 0.629 300 (10 - Power can be calculated by the following fomula: P= I n cosq. . p= (0.640 954) (1o) (0.629 298) o mus 1 p= 44. 3686. wl - - ① Resonaut frequency free an 2x394 x 0.1128 0.0000150 - 122.852 Hz

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