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PRACTICE IT Use the worked example above to help you solve this problem A typical jetliner lands at a speed of 143 mi/h and d
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Answer #1

PRACTICE IT

v = 143 mi / h = 143 * 0.447 = 63.92 m/s

a = 12.1 mi/h/s = 5.409 m / s2

displacement at constant speed = 63.92 * 1.2 = 76.704 m

displacement while decelerating = 63.922 / 2 * 5.409 = 377.7 m

so,

total displacement = 454.38 m

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EXERCISE

Distance covered before brakes are applied = 57.6 * 1.99 = 114.62 m

so,

distance left = 562 - 114.62 = 447.38 m

so,

a = - 57.62 / 2 * 447.38

a = -3.71 m/s2

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