Question

PROBLEM SOLVING: Show free-body diagram, complete solution, unit analysis and box your final answer. Use all the decimal in solutions and final answer.

Answer 1

given

v = 160 mi/h

= 71.53 m.sec

t = 1 sec

a = - 10 mi/h/s

= - 4.47 m/sec²

distance traveled by plane while coasting

a = 0 ,

u = 71.53 m/sec

t = 1 + 1 = 2 sec

$\Delta$x_coasting = ut + 1/2 a t²

= 71.53 x 2

= 143.06 m

distance traveled after brakes are been applied

a = -4.47 m/sec²

u = 71.53 m/sec

$\Delta$x_breaking = v² - u² / 2 a

= ( 0 - 71.53³ ) / - 2 x 4.47

$\Delta$x_breaking = 572.32 m

total distance traveled is = 143.06 + 572.32

= 715.38 m

so the total displacement of the aircraft between touch down on the way runway and coming to rest is 715.38 m