A study of peach trees found that the average number of peaches per tree was 525....
A study of peach trees found that the average number of peaches per tree was 525. The standard deviation of the population is 105 peaches per tree. A scientist wishes to find the 95% confidence interval for the mean number of peaches per tree. How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree? Hint: Round n up the nearest whole number.
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A study of peach trees found that the average number of peaches
per tree was 525....
A study of peach trees found that the average number of peaches per tree was 625....
A study of peach trees found that the average number of peaches per tree was 625. The standard deviation of the population is 35 peaches per tree. A scientist wishes to find the 99% confidence interval for the mean number of peaches per tree. How many trees does she need to sample to obtain an average accurate to within 18 peaches per tree? 4 21 23 26
A study of 55 apple trees showed that the average number of apples per tree was...
A study of 55 apple trees showed that the average number of
apples per tree was 725. The standard deviation of the population
is 100. Which of the following is the confidence interval for the mean
number of apples per tree for all trees?
Recent study stated that if a person chewed gum, the average number of sticks of gum...
Recent study stated that if a person chewed gum, the average number of sticks of gum he or she chewed daily was 8. To test the claim, a researcher selected a random sample of 36 gum chewers and found the mean number of sticks of gum chewed per day was 9. The standard deviation of the population is 1. a) Find a 95% confidence interval for the average number of sticks of gum he or she chewed daily b) Explain...
1) A study of 100 professors showed that the time they spent on the average in...
1) A study of 100 professors showed that the time they spent on the average in creating test questions was 20.0 minutes per question. The standard deviation of the population is 1. Which of the following is the 90% confidence interval for the average number of minutes it takes to create a test question? a) (18.36, 21.64) B)(19.74, 20.26) c)(19.84, 20.16) D)(19.88, 20.12) 2) 1) A previous analysis of paper boxes showed that the standard deviation of their lengths is...
ame: A survey conducted by Sallie Mae and Gallup of 1404 respondents found that 323 students...
ame: A survey conducted by Sallie Mae and Gallup of 1404 respondents found that 323 students paid for their education by student loans. Find the 90% confidence of the true proportion of students who paid for their education by student loans. A survey of 1898 people found that 45% of the adults said that dandelions were the toughest weeds to control in their yards. Find the 95% confidence interval of the true proportion who said that dandelions were the toughest...
You are reading an old report about tree heights in a certain area. The report states (without...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 25.5 m and 29.1 m. The sample size is given as 38 trees, and the document states that the population standard deviation is assumed to be 5.1 m. You wish to determine what confidence level was used to find this confidence interval. What was the sample mean found in the study? What...
Reming The You are reading an old report about tree heights in a certain area. The...
Reming The You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 25.8 m and 28.0 m. The sample size is given as 37 trees, and the document states that the population standard deviation is assumed to be 5.5 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean...
You are reading an old report about tree heights in a certain area. The report states...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 19.2 m and 23.4 m. The sample size is given as 38 trees, and the document states that the population standard deviation is assumed to be 6.2 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean found in...
You are reading an old report about tree heights in a certain area. The report states...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 24.4 m and 26.8 m. The sample size is given as 31 trees, and the document states that the population standard deviation is assumed to be 6.3 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean found in...
Question 9 Outonom A study of nickels showed that the the standard deviation of the weight...
Question 9 Outonom A study of nickels showed that the the standard deviation of the weight of nickels is 150 milligrams. A coin counter manufacturer wishes to find the average weight of a nickel. How many nickels does he need to weigh to obtain an average accurate to within 25 milligrams? 240 confidence interval for the 6 196
A study of 55 apple trees showed that the average number of
apples per tree was 725. The standard deviation of the population
is 100. Which of the following is the confidence interval for the mean
number of apples per tree for all trees?
ame: A survey conducted by Sallie Mae and Gallup of 1404 respondents found that 323 students paid for their education by student loans. Find the 90% confidence of the true proportion of students who paid for their education by student loans. A survey of 1898 people found that 45% of the adults said that dandelions were the toughest weeds to control in their yards. Find the 95% confidence interval of the true proportion who said that dandelions were the toughest...
Reming The You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 25.8 m and 28.0 m. The sample size is given as 37 trees, and the document states that the population standard deviation is assumed to be 5.5 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 19.2 m and 23.4 m. The sample size is given as 38 trees, and the document states that the population standard deviation is assumed to be 6.2 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean found in...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 24.4 m and 26.8 m. The sample size is given as 31 trees, and the document states that the population standard deviation is assumed to be 6.3 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean found in...
Question 9 Outonom A study of nickels showed that the the standard deviation of the weight of nickels is 150 milligrams. A coin counter manufacturer wishes to find the average weight of a nickel. How many nickels does he need to weigh to obtain an average accurate to within 25 milligrams? 240 confidence interval for the 6 196
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