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A 1.4 kg rocket is used to shut the a door. The 22 kg door is...

A 1.4 kg rocket is used to shut the a door. The 22 kg door is 0.9 m wide. The rocket is attached at 0.7 m from the hinge (i.e. not quite the edge). The rocket delivers a continuous FORCE of 18 Newtons. a). What is the combined moment of inertia of the (door + rocket) around the hinges?

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Answer #1

The moment of inrtia of the thin door is

I = 1/3 m w^2

= 1/3 *22* (0.9)^2

=5.94 kg m^2

I = 1/3mr^2 = 1.4 kg (0.7)^2 = 0.228kgm^2

I_ total = 5.94 + 0.686 = 6.16 kg m^2

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