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A professor's office door is 0.94 m wide, 2.0 m high, 4.0 cm thick; has a...

A professor's office door is 0.94 m wide, 2.0 m high, 4.0 cm thick; has a mass of 25 kg , and pivots on frictionless hinges. A "door closer" is attached to door and the top of the door frame. When the door is open and at rest, the door closer exerts a torque of 5.1 N⋅m .

If you let go of the open door, what is its angular acceleration immediately afterward?

What is the moment of inertia of the door?

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Answer #1

(b)

the moment of inertia of the door is

I = mr^2/3

= 25 kg ( 0.94 m)^2/3

=7.36 kg m^2

(a)

T = I alpha

alpha = T/I

=5.1 Nm/7.36 kg m^2

=0.692 rad/s^2

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