A 0.00600 kg bullet traveling horizontally with speed 1.00 103 m/s strikes a 20.8 kg door, embedding itself 11.0 cm from the side opposite the hinges. The 1.00 m wide door is free to swing on its frictionless hinges.
A 0.00600 kg bullet traveling horizontally with speed 
103
What is the angular momentum?
At what angular speed (rad/s) does the door swing open immediately after the collision?
Calculate the total energy of the bullet-door system and determine whether it is less than or equal to the kinetic energy of the bullet before the collision (Answer in Joules).
What is the maximum height (in cm) that the bottom of the door will reach after the collision?
What If? Imagine now that the door is hanging vertically downward, hinged at the top, so that the figure is a side view of the door and bullet during the collision.
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A 0.00600 kg bullet traveling horizontally with speed 1.00 103 m/s strikes a 20.8 kg door, embedding itself 11.0 cm from the side opposite the hinges. The 1.00 m wide door is free to swing on its frictionless hinges.
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