Proof of the distribution of Sample mean:
i.e. The sampling distribution of sample mean follows normal distribution with mean mu and variance sigma^2/n
Central Limit Theorem
The central limit theorem states that:
Given a population with a finite mean ? and a finite non-zero variance ?2, the sampling distribution of the mean approaches a normal distribution with a mean of ? and a variance of ?2/N as N, the sample size, increases.
Proof of Consistent:
5. Suppose X. N(μ, σ2), what is the distribution of the sample mean Σ ? Comment...
Please explain very carefully! 4. Suppose that x = (x1, r.) is a sample from a N(μ, σ2) distribution where μ E R, σ2 > 0 are unknown. (a) (5 marks) Let μ+σ~p denote the p-th quantile of the N(μ, σ*) distribution. What does this mean? (b) (10 marks) Determine a UMVU estimate of,1+ ơZp and justify your answer. 4. Suppose that x = (x1, r.) is a sample from a N(μ, σ2) distribution where μ E R, σ2 >...
DISTRIBUTION OF SAMPLE VARIANCE: Xn ~ N(μ, σ2), where both μ and σ are Problem 4 (25 points). Assume that Xi unknowin 1. Using the exact distribution of the sample variance (Topic 1), find the form of a (1-0) confidence interval for σ2 in terms of quantiles of a chi-square distribution. Note that this interval should not be symmetric about a point estimate of σ2. [10 points] 2. Use the above result to derive a rejection region for a level-o...
Let X = (X1, . . . , Xn) be a random sample of size n with mean μ and variance σ2. Consider Tm i=1 (a) Find the bias of μη(X) for μ. Also find the bias of S2 and ỡXX) for σ2. (b) Show that Hm(X) is consistent. (c) Suppose EIXI < oo. Show that S2 and ỡXX) are consistent. Let X = (X1, . . . , Xn) be a random sample of size n with mean μ...
4(25 points) Let X be a random variable with mean μ = E(X) and σ2 V(X). Let X = n Σ_1Xī be X2 + Xs) be the average of the the sample mean from a random sample (X X. Let X (X first three observations. (a) Prove that X is an unbiased estimator for μ. Prove that X is also an unbiased estimator for μ. (b) Explain that X is a consistent estimator for μ. Explain why X is not...
Suppose a random variable x is normally distributed with μ = 17.5 and σ = 5.8 . According to the Central Limit Theorem, for samples of size 8: The mean of the sampling distribution for x¯ ( x bar ) is: 1
R commands 2) Illustrating the central limit theorem. X, X, X, a sequence of independent random variables with the same distribution as X. Define the sample mean X by X = A + A 2 be a random variable having the exponential distribution with A -2. Denote by -..- The central limit theorem applied to this particular case implices that the probability distribution of converges to the standard normal distribution for certain values of u and o (a) For what...
A population of values has a normal distribution with μ=134.3μ=134.3 and σ=62.4σ=62.4. You intend to draw a random sample of size n=137n=137.What is the mean of the distribution of sample means?μ¯x=μx¯= What is the standard deviation of the distribution of sample means?(Report answer accurate to 2 decimal places.)σ¯x=σx¯=
, X,' up N(μ, σ2), with σ2 known. Let μη-Xn + 5. Let Xi, of u be an estimator (a) Is ,hi an unbiased estimator for μ? (b) For a particular fixed n, find the distribution of (c) Find the mean squared error (MSE) of . (d) Prove that μη is consistent for μ
Suppose x has a distribution with μ = 35 and σ = 18. (a) If random samples of size n = 16 are selected, can we say anything about the x distribution of sample means? Yes, the x distribution is normal with mean μ x = 35 and σ x = 4.5. No, the sample size is too small. Yes, the x distribution is normal with mean μ x = 35 and σ x = 18. Yes, the x distribution...
Suppose x has a distribution with μ = 32 and σ = 17. (a) If random samples of size n = 16 are selected, can we say anything about the x distribution of sample means? No, the sample size is too small. Yes, the x distribution is normal with mean μ x = 32 and σ x = 17. Yes, the x distribution is normal with mean μ x = 32 and σ x = 1.1. Yes, the x distribution...