Question

Replace the loading system by an equivalent resultant force and couple moment at 0.

X 2016 aft В F = (21-4j +56)1b -24 || 1-244t-aft Mo 10 16.67 Us So16 Replace the loading system by on equivalent resultant force and couple moment at o.

Answer 1

N to-ordinates of various points: A(-2,6, 0), 4+ B(-4, 6, o), ft c(-1,0, 2), At D(0, 6, o), ft Forces F = (22-49 +5%), u a = -50 ê, cb Tho = – 10%, lb-ft (-1+4) i + (0-6) ŷ + (2-0) Ê (from co-ordinates) FCB -31 -69 +2 unit vector fo= -32-69 + 20 + (-31 - 67 + 2€), 3² +6² +22 F CD 20 (-31-6j+26). 6. Equivalent force - & - A to + B+ Ro - (zi-uſ+ sé ) - sof + **(-3? -o+28) ľ = -6,571 ↑ -21, 143 ] -39.286 h, is Equivalent moment at o to = MA Moment due. 1 وس 6 O = 301 -j (-10) + Ê (8-12) = 301 +10] -4² 2 -4 $

moment due to WA WA - j k о е = - 300 ? - 100 lbft 0 0 - 50 moment due to Fn = 7x Fr MB - MB = j k -6 = 1(-240) - § (-160) + † ( 4 - 360) -120 7 40 = 1 / (-240? + 160 3+1206), (b-tt Mo=MA+MWA t mo + mo = 301 + 10] -4€ -200 ? - 1003 - 240 p + 160 9 + 120 P-10) n = -308.511 - 77.143 + 13.1437, 4-++