Question

Replace the loading System by an equivalent resultant force and couple momentato lift IC 30lbs aft T - Focai-sýrsk) 16 aft pfe 10lb.ft Mo 67 W: 50 lb

Answer 1

I have replaced the loading system by an equivalent resultant force and couple moment at 0.
Given Data:- 201bs 것 oft W-50 lb Forces : - = (27-49+5€ Db Wa= -50 K 10 [:- because it's acting downrus a mín = -loî, lb-ft. lolbift Co-ordinates for diffevent points k A 62,6,0) ft B64,6,0)ft CG1,0,2) ft D(0,6, 0) ft Ves = (1+4) î+ (0-6).5+ (2-0) Af from figure and (Co-ordinates -31-6ỉ +2K -37-it Unit vector 3²+6²+22 '/7 (-311-6] +2²).ft (-3^-6 +28). 16. F = Fa +Fe +Fc+FO (Equivalent forces) (27-4h+5R)-50 (si-aî+28 F = -6.571 – 21.143 – 39.286 Êilb. OCB Үср 20 FB =FB X VCD = 20 50k +

* Moment at 0 :- Moment due to FÅ = VÀ X FA = MA 301-Î (-10) +ħ (8-12) = 30 +10j_4K j 6 22 OT O -4. * NOW, Moment because of Wa = TĂ xWA j Mwa у о 2-3001-100] Ibift -2 6 0 50 i -4 + -6 -60 -120 F 40 7 B 7 *and, the moment due to FR = *FB =MB MB (246)-3(180)+ ( 1480 - 340) +62401 +160ĩ +1208)1640 ... Mo = MA +MWA TMB tho Lo Boi + loộ– –zon-los-603 + 12017 Ñ -10 Ì Moz-308.577 _771439 + 13.143 Â (buft. moments about