Question

A system absorbs 187 kJ of heat and the surroundings do 120 kJ of work on...

A system absorbs 187 kJ of heat and the surroundings do 120 kJ of work on the system.

What is the change in internal energy of the system?

Express the internal energy in kilojoules to three significant figures.

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Answer #1

dQ = 187 kJ

dW = 120 kJ

from first law of thermodynamic

Initially the system absorbs energy ( dQ=187 kJ) as heat. Then the surroundings do work (dW=120kJ) on the system, so the system gains 120 kJ more. The total energy change is = heat + work

dU = dQ + dW

dU = 187 + 120

dU = 307 kJ

change in internal energy = 307 kJ

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