A system absorbs 187 kJ of heat and the surroundings do 120 kJ of work on the system.
What is the change in internal energy of the system?
Express the internal energy in kilojoules to three significant figures.
dQ = 187 kJ
dW = 120 kJ
from first law of thermodynamic
Initially the system absorbs energy ( dQ=187 kJ) as heat. Then the surroundings do work (dW=120kJ) on the system, so the system gains 120 kJ more. The total energy change is = heat + work
dU = dQ + dW
dU = 187 + 120
dU = 307 kJ
change in internal energy = 307 kJ
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