Question

A system absorbs 12  of heat from the surroundings; meanwhile, 28  of work is done BY the system....

A system absorbs 12  of heat from the surroundings; meanwhile, 28  of work is done BY the system. What is the change of the internal energy  of the system?

-40 J
-16 J
16 J
40 J
0 0
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Answer #1

By first law of thermodynamics,

Q = ∆U + W

( Where, Q is heat absorbed, ∆U is change in internal energy, W is work done by system)

12 = ∆U + 28

∆U = -16 J

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