A system absorbs 12 of heat from the surroundings; meanwhile, 28 of work is done BY the system. What is the change of the internal energy of the system?
-40 J |
-16 J |
16 J |
40 J |
By first law of thermodynamics,
Q = ∆U + W
( Where, Q is heat absorbed, ∆U is change in internal energy, W is work done by system)
12 = ∆U + 28
∆U = -16 J
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