Question

ealer is placed underwater. What is the buoyant force on the iron? 2. A 500g piece of Iron (D = 7.8 g/cc) is placed underwater. What is the buova What is the iron's apparent weight? 3. If the iron in #2 were placed in alcohol (D = 0.8 g/cc) would its apparent weight be more, less or the same as it was in #2? Explain. A. Allul a travelling through a pipe of radius 4 inches. It's speed is 1 m/s. If the pipe narrows to a of 2 inches, what would the fluids speed be in the narrow part? of 2 inches
2 and 3 please

Answer 1

Buoyant force exerted by fluid = weight of fraction of volume (upward direction) merged in fluid . (downward direction) -acceleration due to gravity to = my mass of object = (0.5kg)(9.8 m/s) = 4.9 N] As per the Archimedes Principle Apparent weight = Total weight - weight of displaced fluid weight of displaced liquid = preg volum volume Volume of displaced liquid L density = volume of object = mass/density (idensity was. = soog = 64.10 (.C. volume) 7.8glec 16 ml xlos me we know density of water = 10x103 kg/m² = 1g/cc weight of clisplaced liquid = (-oxid86g |us) (6:41x17?m?) (9-8 m/s) = 0.63 N Thus apparent weight = 4.9 N – 0.63 N = 4.27 N] ② density of alchohol is less than water, it's weight will be less than weight of water displaced. There There fore the apparent weight will be more than the weight which is obtained in Question no. 2. Because Total weight of object Apparent weight = Total weight of object - weight of displaced liquid.