Question

PYTHON QUESTION

2. Write a function called first_day_greater that takes two lists, L1 and L2 , representing the daily measured weights of rat 1 and rat 2, respectively, and returns the index of the first day for which the weight for the fist rat is greater than the weight of the second rat.If there are no such days then the function should return -1. You may NOT assume that L1 and L2 are the same length. Use the following to test your program: 1 f name --" main ": L1- 15.1, 17.3, 12.3, 16.4 L2 = [ 15.0, 17.7, 12.5, 16.9 ] print ("Test 1: (".format( first_day_greater(L1,L2) )) L2= [ 15.6, 17.9, 18.2, 16.5, 12.7 ] print("Test 2: (".format( first_day_greater(L1,L2) )) L2 = [ 15.9, 18.8, 11.4 ] print ("Test 3: 0".format( first_day_greater(L1,L2))

Answer 1

The following is the code for your requirements as in the instructions.
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The output and screenshot is at end of this answer.

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Here is the code.
//File: listgreater.py

#Method to return the index of L1 when L1[i] > L2[i]
def first_day_greater(L1, L2):
#Iterate from first index to MIN of len of either list
for i in range(0, min(len(L1), len(L2))):
#If the value at this index in list L1 is greater than L2, return this index
if L1[i] > L2[i]:
return i
#No values in L1 is greater than L2
return -1
#Tests
if __name__ == '__main__':
L1 = [15.1, 17.3, 12.3, 16.4]
L2 = [15.0, 17.7, 12.5, 16.9]
print("Test 1: {}".format( first_day_greater(L1, L2)))
L2 = [15.6, 17.9, 18.2, 16.5, 12.7]
print("Test 2: {}".format( first_day_greater(L1, L2)))
L2 = [15.9, 18.8, 11.4]
print("Test 3: {}".format( first_day_greater(L1, L2)))

And here is the output when you execute the code
//Output: