Question

Please show full solutions.

Answers:

a) 1.416e-10 C

b) 12 V

c) -8.496e-10 J

A parallel plate capacitor with plate area A = 2 cm^2 and plate separation d = 0.3 mm is charged using a 24 V battery. Find the charge on each plate when the capacitor is fully charged. The capacitor is then disconnected from the battery and then a dielectric with dielectric constant of 2.0 is fully inserted between the plates. Calculate the resulting potential difference between the two plates of the capacitor. Calculate the amount of work which was done to insert the dielectric.

Thanks!

Answer 1

a) 8.85 x10-12x2x10^m 0.3x10 5.9x10-12F -24x5.9x 10-12 -1.416x10-10c b) New capacitance -2x5.9x10-12 -11.8x10-12F 0_1.416x10-10 С 11.8x10-12

c) Amount of work done 1.416x10-0) 2 | =-8.496 x 10-10J 30.10 11.8x10-u 5.9×10-u