Question

The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a...

The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a separation of 8.80 mm are charged to a 130-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with κ = 6.5 is inserted between the plates of the capacitor.

(a) What is the charge on the capacitor before and after the dielectric is inserted?

Qi

= ___C

Qf

= ____C


(b) What is the capacitance of the capacitor after the dielectric is inserted?
___F

(c) What is the potential difference between the plates of the capacitor after the dielectric is inserted?
____V

(d) What is the magnitude of the change in the energy stored in the capacitor after the dielectric is inserted?
____J

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of...

    A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness ℓ = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642). Determine the initial capacitance of the air-filled capacitor. Determine the charge on the...

  • A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of...

    A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness ℓ = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642). Determine the electric field in the dielectric. Determine the free charge on the...

  • The parallel plates in a capacitor, with a plate area of 9.90 cm2 and an air-filled...

    The parallel plates in a capacitor, with a plate area of 9.90 cm2 and an air-filled separation of 2.30 mm, are charged by a 4.10 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 6.50 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.

  • The parallel plates in a capacitor, with a plate area of 9.00 cm2 and an air-filled...

    The parallel plates in a capacitor, with a plate area of 9.00 cm2 and an air-filled separation of 3.30 mm, are charged by a 5.40 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.10 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates

  • The parallel plates in a capacitor, with a plate area of 9.00 cm2 and an air-filled...

    The parallel plates in a capacitor, with a plate area of 9.00 cm2 and an air-filled separation of 3.30 mm, are charged by a 5.40 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.10 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.

  • The parallel plates in a capacitor, with a plate area of 5.30 cm2 and an air-filled...

    The parallel plates in a capacitor, with a plate area of 5.30 cm2 and an air-filled separation of 4.60 mm, are charged by a 3.60 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 6.00 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.

  • The parallel plates in a capacitor, with a plate area of 6.60 cm2 and an air-filled...

    The parallel plates in a capacitor, with a plate area of 6.60 cm2 and an air-filled separation of 3.30 mm, are charged by a 4.20 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 7.60 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates. (a) Number i Units ► (b)...

  • The parallel plates in a capacitor, with a plate area of 7.60 cm2 and an air-filled...

    The parallel plates in a capacitor, with a plate area of 7.60 cm2 and an air-filled separation of 2.70 mm, are charged by a 6.00 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.30 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates. (a) Number Units (b) Number Units...

  • A parallel-plate air capacitor of area A = 12.1 cm2 and plate separation of d = 3.90...

    A parallel-plate air capacitor of area A = 12.1 cm2 and plate separation of d = 3.90 mm is charged by a battery to a voltage of 53.0 V. a)What is the charge on the capacitor?  b)If a dielectric material with κ = 5.00 is inserted so that it fills the volume between the plates (with the capacitor still connected to the battery), how much additional charge will flow from the battery onto the positive plate?

  • The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such...

    The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such that the electric field is at the breakdown value. By what factor will the maximum charge on the plates increase when polystyrene is inserted between the plates? (The dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 2.40 x 107 V/m. The dielectric constant of polystyrene is 2.56. Supporting Materials Physical Constants Additional Materials Tutorial

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT