Question

Question 4 Next, we turn to substep C. Using the answers from parts 2 and 3, you can find the net electrostatic force on particle #3. Enter symbolic expressions for the two components F 3net = F 31 + F 32, F3net,x and F3net,y. Both answers can be in terms of the following symbols: 91, 92, 93, 1, 60, L and y. Don't forget all you have learned about vector addition. F3net x = Edit F3net,y = Edit Attempts: 0 of 6 used SAVE FOR LATER SUBMIT ANSWER

Answer 1

from coulomb's law, I Failure and here r3,= [ty Fail = un 80 alty For 2 = 1 a X Letry F31,2 = TEO 1 1 2 + y 27 3/2 Fally = 1 F3il sine - 4TTEO [2742 Very2 9 193 L Falny = 4780 993 y (LP+y213/2 from coulomb's law, 1 Fal - I 2293 132 = 22+y2 IFBal - 4TTEO 832² Foal = 4TTEO 2 tyz L F32, x = Faal coso - YTTEO 23 x 2 Lety 2 [2442 F32, x- YTTEO (12+ y 2) 312 F22, x-it 929 3L Fax y = uten 9a 93 ya (24423/2 Fanet, x = Fax +F32,x=1 & L 41 EO (L² + y 233/2 Faner, y = 83, y + F32, y = 23 y UTEO ( [ty 23/2 (91 tona)