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Question 8 8 pts The Earth takes slightly less than one day to complete one rotation about the axis passing through its poles
D Question 11 8 pts A pirates treasure chest has a rectangular top with a dimension of 0.5 m and 1m. It lies 17 m below the
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Answer #1

Question 8 : The angular speed of the Earth about its axis which will be given by -

\omega = (2\pi rad) / T

\omega = [(6.28 rad) / (72976 s)]

\omega = 8.60 x 10-5 rad/s

Question 9 : The angular acceleration of a point on the wheel which will be given by -

\omegaf = \omega0 + \alpha t

(15 rev/s) = (35 rev/s) + \alpha (9.92 s)

[(15 rev/s) - (35 rev/s)] = \alpha (9.92 s)

(-20 rev/s) = \alpha (9.92 s)

\alpha = [(-20 rev/s) / (9.92 s)]

\alpha = - 2.01 rev/s2

Question 10 : If the net applied torque is 800 N.m, what is the moment of inertia of the merry-go-round?

using a rotational motion (i), we have

\omegaf = \omega0 + \alpha t

(1.2 rad/s) = (0 rad/s) + \alpha (12.16 s)

\alpha = [(1.2 rad/s) / (12.16 s)]

\alpha = 0.0986 rad/s2

We know that, \tau = I \alpha\Leftrightarrow I = \tau / \alpha

I = [(800 N.m) / (0.0986 rad/s2)]

I = 8113.5 kg.m2

Question 11 : The pressure acting on the treasure chest which will be given by -

P = \rhowater g h

P = [(1000 kg/m3) (9.8 m/s2) (17 m)]

P = 166600 Pa

We know that, Pabsolute = Patmospheric + Pwater

Pabsolute = [(1 x 105 Pa) + (166600 Pa)]

Pabsolute = 266600 Pa

What is the magnitude of the force that acts on the rectangular top?

F = Pabsolute A

F = (266600 Pa) [(0.5 m) (1 m)]

F = 133300 N

Question 12 : What volume does 7.49 kg of carbon dioxide occupy at standard temperature and pressure?

we know that, V = m / \rho

V = [(7.49 kg) / (1.98 kg/m3)]

V = 3.78 m3

Question 13 : If the radius of a piston is 0.69 m, what is the maximum mass that can be raised using this piston?

using a formula, we have

F = P A = (4 x 105 Pa) (\pi r2)

F = [(4 x 105 Pa) (3.14) (0.69 m)2]

F = 597981.6 N

we know that, F = m a

m = [(597981.6 N) / (9.8 m/s2)]

m = 61018.5 kg

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