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Due April 17,2019 m IS weda Look over the commands and examples in the Matlab Overview documents available on Blackboard in t solve problem 3 4 snd 5
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Answer #1

MATLAB Script (run it as a script, NOT from command window):

close all
clear
clc

A = magic(8);

% Question 3
N = null(A);
disp('Basis for Nul A ='), disp(N)
C = colspace(sym(A));
disp('Basis for Col A ='), disp(C)

% Question 4
R = colspace(sym(A'));
disp('Basis for Row A ='), disp(R)

% Question 5
D = magic(9)
is_invertible(D);
E = magic(10)
is_invertible(E);

function [] = is_invertible(A)
if isequal(rank(A), min(size(A)))
disp('Input matrix is invertible.')
else
disp('Input matrix is not invertible.')
end
end

Output:

Basis for Nul A =
0.4461 -0.0045 0.1630 -0.1376 0.4624
0.0316 -0.5347 0.0588 0.2851 0.4791
0.1563 0.5031 0.6123 -0.1575 -0.1384
-0.8174 0.0572 0.2353 0.0846 0.1006
0.2530 -0.3858 0.1346 0.2465 -0.6726
-0.1707 -0.2984 -0.2570 -0.6808 -0.2206
-0.0172 0.3300 -0.4141 0.5532 -0.1201
0.1182 0.3330 -0.5329 -0.1935 0.1096
Basis for Col A =
[ 1, 0, 0]
[ 0, 1, 0]
[ 0, 0, 1]
[ 1, 3, -3]
[ 1, 4, -4]
[ 0, -3, 4]
[ 0, -4, 5]
[ 1, 7, -7]
Basis for Row A =
[ 1, 0, 0]
[ 0, 1, 0]
[ 0, 0, 1]
[ 1, 3, -3]
[ 1, 4, -4]
[ 0, -3, 4]
[ 0, -4, 5]
[ 1, 7, -7]
D =
47 58 69 80 1 12 23 34 45
57 68 79 9 11 22 33 44 46
67 78 8 10 21 32 43 54 56
77 7 18 20 31 42 53 55 66
6 17 19 30 41 52 63 65 76
16 27 29 40 51 62 64 75 5
26 28 39 50 61 72 74 4 15
36 38 49 60 71 73 3 14 25
37 48 59 70 81 2 13 24 35
Input matrix is invertible.
E =
92 99 1 8 15 67 74 51 58 40
98 80 7 14 16 73 55 57 64 41
4 81 88 20 22 54 56 63 70 47
85 87 19 21 3 60 62 69 71 28
86 93 25 2 9 61 68 75 52 34
17 24 76 83 90 42 49 26 33 65
23 5 82 89 91 48 30 32 39 66
79 6 13 95 97 29 31 38 45 72
10 12 94 96 78 35 37 44 46 53
11 18 100 77 84 36 43 50 27 59
Input matrix is not invertible.

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