Question

For the beam shown, determine the reaction at the roller support when Wo 10 kips/ft. (Round the final answer to two decimal places.) wWo(/L A В L 12 ft The reaction at the roller support is kips f

Answer 1

DATE Wo W: wo (2) Wo so kips/ft --- 12 ft ff.) of Elastic curve. EI dty = -W(2) dx4 47 EI day = - Wo (2) 2 - dz4 Integrating and twice. EI du Wo x3 +01 - dx3 ² 3 EI d²4 - Wo x4 +Cr +62 - dr2 2² 12 Es dey. Vo shear fozce and EI dy - M - Bending dz3 moment boundary conditions at x = 0 M=0 dra - at x=0 C2=0 /= Ay C. Ay Integrating.

+(3 Er dy dx - Wo L2 60 again EIY: -W x' + Ay xo +(37464 22 360 at x = 0 , y = 0 at X= L , dyldx=0 ☆ Oo - My do 4 C3 - Cz: WOL3 - A42² So, a EIy: - Wo ert Ay 2+ (W0 L3 - Aq4° ---6 60 2 22 360 Now at x= L > y=0 03 we have eat ay (angl. 2. Ande? 37 Wol4 Wol4 2 360 60 Wol 24 Ay = Wol so, qg: tox)2 -> My = 5 Kips (4) 24
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