1) The reaction has a positive energy of activation. This means that the transition state has a higher energy than the reactants and the products. The free energy diagram is drawn below.
2) The Arrhenius equation is written as
ln k2/k1 = -Ea/R*(1/T2 – 1/T1)
where k1 and k2 are the reaction rates at temperatures T1 and T2.
Given T1 = 27°C = (27 + 273) K = 300 K and T2 = 53.4°C = (53.4 + 273) K = 326.4 K, plug in values and get
ln k2/k1 = -(55.3 kJ/mol)/(8.314 J/mol.K)*[1/(326.4 K) – 1/(300 K)]
= -[(55.3 kJ/mol)*(1000 J)/(1 k)]/(8.314 J/mol.K)*(-0.0002696 K-1)
= 1.7932
=====> k2/k1 = exp (1.7932)
=====> k2/k1 = 6.008 ≈ 6.0
=====> k2 = 6.0*k1
The rate of the reaction increases 6 times (ans).
I, The reaction A→B+C has an activaれon energy CEA OF $5.3.Draus reachion londscape LA vs Rx...