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Assume that females have pulse rates that are normally distributed with a mean of 75.0 beats per minute and a standard deviat
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Answer #1

Here we have given that

Xi: Pulse rates of females in beats per minute

\mu = Populaiton mean = 75 beats per minute

\sigma = Population Standard deviation = 12.5 beats per minute

(A)

Now we want to calculate the probability that adult women have pulse rates with a sample mean less than 78 beats per minute?

i.e P( \bar x < 78) =?

P( \bar x < 78) = P (z < \frac{\bar x- \mu } { \frac{\sigma}{\sqrt(n)}})

= P (z < \frac{78-75 } { \frac{12.5}{\sqrt(16)}})

=P (z < \frac{3 } {3.125})

=P (z < 0.96)

=0.8315 Using standard normal z table see value corresponding z score 0.96

The probability that adult women have pulse rates with a sample mean less than 78 beats per minute is 0.8315

i.e. P( \bar x < 78) = 0.8315

(B)

Here, we have given that

Assume that the females have pulse rates that are normally distributed with population parameters which refers that the original population distribution is normal and then we took the 16 females sample randomly from the population.

Hence, here option D is correct

Since the original population has a normal distribution. the distribution of sample means is the normal distribution for any sample size.

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